8(1z+4)=5(13+1z)

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Solution for 8(1z+4)=5(13+1z) equation:


Simplifying
8(1z + 4) = 5(13 + 1z)

Reorder the terms:
8(4 + 1z) = 5(13 + 1z)
(4 * 8 + 1z * 8) = 5(13 + 1z)
(32 + 8z) = 5(13 + 1z)
32 + 8z = (13 * 5 + 1z * 5)
32 + 8z = (65 + 5z)

Solving
32 + 8z = 65 + 5z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-5z' to each side of the equation.
32 + 8z + -5z = 65 + 5z + -5z

Combine like terms: 8z + -5z = 3z
32 + 3z = 65 + 5z + -5z

Combine like terms: 5z + -5z = 0
32 + 3z = 65 + 0
32 + 3z = 65

Add '-32' to each side of the equation.
32 + -32 + 3z = 65 + -32

Combine like terms: 32 + -32 = 0
0 + 3z = 65 + -32
3z = 65 + -32

Combine like terms: 65 + -32 = 33
3z = 33

Divide each side by '3'.
z = 11

Simplifying
z = 11

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