8(2(x+)/4-7)+40=8

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Solution for 8(2(x+)/4-7)+40=8 equation: 



8(2(x+)/4-7)+40=8

We move all terms to the left:

8(2(x+)/4-7)+40-(8)=0

We add all the numbers together, and all the variables

8(2(+x)/4-7)+40-8=0

We add all the numbers together, and all the variables

8(2(+x)/4-7)+32=0

We multiply all the terms by the denominator


8(2(+x)+32*4-7)=0

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