8(2+3x)+1=x-10(x+1)

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Solution for 8(2+3x)+1=x-10(x+1) equation: 



8(2+3x)+1=x-10(x+1)

We move all terms to the left:

8(2+3x)+1-(x-10(x+1))=0

We add all the numbers together, and all the variables

8(3x+2)-(x-10(x+1))+1=0

We multiply parentheses

24x-(x-10(x+1))+16+1=0



We calculate terms in parentheses: -(x-10(x+1)), so:

x-10(x+1)

We multiply parentheses

x-10x-10

We add all the numbers together, and all the variables

-9x-10

Back to the equation:

-(-9x-10)



We add all the numbers together, and all the variables

24x-(-9x-10)+17=0

We get rid of parentheses

24x+9x+10+17=0

We add all the numbers together, and all the variables

33x+27=0

We move all terms containing x to the left, all other terms to the right

33x=-27

x=-27/33

x=-9/11

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