8(2+3z)+1=z-10(z+1)

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Solution for 8(2+3z)+1=z-10(z+1) equation:


Simplifying
8(2 + 3z) + 1 = z + -10(z + 1)
(2 * 8 + 3z * 8) + 1 = z + -10(z + 1)
(16 + 24z) + 1 = z + -10(z + 1)

Reorder the terms:
16 + 1 + 24z = z + -10(z + 1)

Combine like terms: 16 + 1 = 17
17 + 24z = z + -10(z + 1)

Reorder the terms:
17 + 24z = z + -10(1 + z)
17 + 24z = z + (1 * -10 + z * -10)
17 + 24z = z + (-10 + -10z)

Reorder the terms:
17 + 24z = -10 + z + -10z

Combine like terms: z + -10z = -9z
17 + 24z = -10 + -9z

Solving
17 + 24z = -10 + -9z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '9z' to each side of the equation.
17 + 24z + 9z = -10 + -9z + 9z

Combine like terms: 24z + 9z = 33z
17 + 33z = -10 + -9z + 9z

Combine like terms: -9z + 9z = 0
17 + 33z = -10 + 0
17 + 33z = -10

Add '-17' to each side of the equation.
17 + -17 + 33z = -10 + -17

Combine like terms: 17 + -17 = 0
0 + 33z = -10 + -17
33z = -10 + -17

Combine like terms: -10 + -17 = -27
33z = -27

Divide each side by '33'.
z = -0.8181818182

Simplifying
z = -0.8181818182

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