8(2+4x)+6(6-x)=0

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Solution for 8(2+4x)+6(6-x)=0 equation: 



8(2+4x)+6(6-x)=0

We add all the numbers together, and all the variables

8(4x+2)+6(-1x+6)=0

We multiply parentheses

32x-6x+16+36=0

We add all the numbers together, and all the variables

26x+52=0

We move all terms containing x to the left, all other terms to the right

26x=-52

x=-52/26

x=-2

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