8(2+c)=7(c-1)

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Solution for 8(2+c)=7(c-1) equation: 


Simplifying
8(2 + c) = 7(c + -1)
(2 * 8 + c * 8) = 7(c + -1)
(16 + 8c) = 7(c + -1)

Reorder the terms:
16 + 8c = 7(-1 + c)
16 + 8c = (-1 * 7 + c * 7)
16 + 8c = (-7 + 7c)

Solving
16 + 8c = -7 + 7c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-7c' to each side of the equation.
16 + 8c + -7c = -7 + 7c + -7c

Combine like terms: 8c + -7c = 1c
16 + 1c = -7 + 7c + -7c

Combine like terms: 7c + -7c = 0
16 + 1c = -7 + 0
16 + 1c = -7

Add '-16' to each side of the equation.
16 + -16 + 1c = -7 + -16

Combine like terms: 16 + -16 = 0
0 + 1c = -7 + -16
1c = -7 + -16

Combine like terms: -7 + -16 = -23
1c = -23

Divide each side by '1'.
c = -23

Simplifying
c = -23

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