8(2+c)=7(c-2)

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Solution for 8(2+c)=7(c-2) equation:


Simplifying
8(2 + c) = 7(c + -2)
(2 * 8 + c * 8) = 7(c + -2)
(16 + 8c) = 7(c + -2)

Reorder the terms:
16 + 8c = 7(-2 + c)
16 + 8c = (-2 * 7 + c * 7)
16 + 8c = (-14 + 7c)

Solving
16 + 8c = -14 + 7c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-7c' to each side of the equation.
16 + 8c + -7c = -14 + 7c + -7c

Combine like terms: 8c + -7c = 1c
16 + 1c = -14 + 7c + -7c

Combine like terms: 7c + -7c = 0
16 + 1c = -14 + 0
16 + 1c = -14

Add '-16' to each side of the equation.
16 + -16 + 1c = -14 + -16

Combine like terms: 16 + -16 = 0
0 + 1c = -14 + -16
1c = -14 + -16

Combine like terms: -14 + -16 = -30
1c = -30

Divide each side by '1'.
c = -30

Simplifying
c = -30

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