8(2+t)-5(t+1)=t

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Solution for 8(2+t)-5(t+1)=t equation: 



8(2+t)-5(t+1)=t

We move all terms to the left:

8(2+t)-5(t+1)-(t)=0

We add all the numbers together, and all the variables

8(t+2)-5(t+1)-t=0

We add all the numbers together, and all the variables

-1t+8(t+2)-5(t+1)=0

We multiply parentheses

-1t+8t-5t+16-5=0

We add all the numbers together, and all the variables

2t+11=0

We move all terms containing t to the left, all other terms to the right

2t=-11

t=-11/2

t=-5+1/2

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