8(2-3x)-11=7(3x-2)+10

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Solution for 8(2-3x)-11=7(3x-2)+10 equation: 



8(2-3x)-11=7(3x-2)+10

We move all terms to the left:

8(2-3x)-11-(7(3x-2)+10)=0

We add all the numbers together, and all the variables

8(-3x+2)-(7(3x-2)+10)-11=0

We multiply parentheses

-24x-(7(3x-2)+10)+16-11=0



We calculate terms in parentheses: -(7(3x-2)+10), so:

7(3x-2)+10

We multiply parentheses

21x-14+10

We add all the numbers together, and all the variables

21x-4

Back to the equation:

-(21x-4)



We add all the numbers together, and all the variables

-24x-(21x-4)+5=0

We get rid of parentheses

-24x-21x+4+5=0

We add all the numbers together, and all the variables

-45x+9=0

We move all terms containing x to the left, all other terms to the right

-45x=-9

x=-9/-45

x=1/5

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