8(2-3x)-11=7(3x-2)+10

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Solution for 8(2-3x)-11=7(3x-2)+10 equation:



8(2-3x)-11=7(3x-2)+10
We move all terms to the left:
8(2-3x)-11-(7(3x-2)+10)=0
We add all the numbers together, and all the variables
8(-3x+2)-(7(3x-2)+10)-11=0
We multiply parentheses
-24x-(7(3x-2)+10)+16-11=0
We calculate terms in parentheses: -(7(3x-2)+10), so:
7(3x-2)+10
We multiply parentheses
21x-14+10
We add all the numbers together, and all the variables
21x-4
Back to the equation:
-(21x-4)
We add all the numbers together, and all the variables
-24x-(21x-4)+5=0
We get rid of parentheses
-24x-21x+4+5=0
We add all the numbers together, and all the variables
-45x+9=0
We move all terms containing x to the left, all other terms to the right
-45x=-9
x=-9/-45
x=1/5

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