8(2-q-2q+6+1)=3-(8-3q)

Solution for 8(2-q-2q+6+1)=3-(8-3q) equation:

8(2-q-2q+6+1)=3-(8-3q)

We move all terms to the left:

8(2-q-2q+6+1)-(3-(8-3q))=0

We add all the numbers together, and all the variables

8(-3q+9)-(3-(-3q+8))=0

We multiply parentheses

-24q-(3-(-3q+8))+72=0


We calculate terms in parentheses: -(3-(-3q+8)), so:

3-(-3q+8)

determiningTheFunctionDomain
-(-3q+8)+3

We get rid of parentheses

3q-8+3

We add all the numbers together, and all the variables

3q-5

Back to the equation:

-(3q-5)


We get rid of parentheses

-24q-3q+5+72=0

We add all the numbers together, and all the variables

-27q+77=0

We move all terms containing q to the left, all other terms to the right

-27q=-77

q=-77/-27

q=2+23/27