8(2-x)-4(x-2)=8

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Solution for 8(2-x)-4(x-2)=8 equation: 



8(2-x)-4(x-2)=8

We move all terms to the left:

8(2-x)-4(x-2)-(8)=0

We add all the numbers together, and all the variables

8(-1x+2)-4(x-2)-8=0

We multiply parentheses

-8x-4x+16+8-8=0

We add all the numbers together, and all the variables

-12x+16=0

We move all terms containing x to the left, all other terms to the right

-12x=-16

x=-16/-12

x=1+1/3

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