8(2b+1)+(17b-5)=0

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Solution for 8(2b+1)+(17b-5)=0 equation:


Simplifying
8(2b + 1) + (17b + -5) = 0

Reorder the terms:
8(1 + 2b) + (17b + -5) = 0
(1 * 8 + 2b * 8) + (17b + -5) = 0
(8 + 16b) + (17b + -5) = 0

Reorder the terms:
8 + 16b + (-5 + 17b) = 0

Remove parenthesis around (-5 + 17b)
8 + 16b + -5 + 17b = 0

Reorder the terms:
8 + -5 + 16b + 17b = 0

Combine like terms: 8 + -5 = 3
3 + 16b + 17b = 0

Combine like terms: 16b + 17b = 33b
3 + 33b = 0

Solving
3 + 33b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 33b = 0 + -3

Combine like terms: 3 + -3 = 0
0 + 33b = 0 + -3
33b = 0 + -3

Combine like terms: 0 + -3 = -3
33b = -3

Divide each side by '33'.
b = -0.09090909091

Simplifying
b = -0.09090909091

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