8(2c+3)-(c-2)=7

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Solution for 8(2c+3)-(c-2)=7 equation: 



8(2c+3)-(c-2)=7

We move all terms to the left:

8(2c+3)-(c-2)-(7)=0

We multiply parentheses

16c-(c-2)+24-7=0

We get rid of parentheses

16c-c+2+24-7=0

We add all the numbers together, and all the variables

15c+19=0

We move all terms containing c to the left, all other terms to the right

15c=-19

c=-19/15

c=-1+4/15

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