8(2c+3)-(c-2)=7

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Solution for 8(2c+3)-(c-2)=7 equation:



8(2c+3)-(c-2)=7
We move all terms to the left:
8(2c+3)-(c-2)-(7)=0
We multiply parentheses
16c-(c-2)+24-7=0
We get rid of parentheses
16c-c+2+24-7=0
We add all the numbers together, and all the variables
15c+19=0
We move all terms containing c to the left, all other terms to the right
15c=-19
c=-19/15
c=-1+4/15

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