8(2c-5)=16c-40

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Solution for 8(2c-5)=16c-40 equation: 



8(2c-5)=16c-40

We move all terms to the left:

8(2c-5)-(16c-40)=0

We multiply parentheses

16c-(16c-40)-40=0

We get rid of parentheses

16c-16c+40-40=0

We add all the numbers together, and all the variables

=0

c=0/1

c=0

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