8(2f-2)=7(3f+22)

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Solution for 8(2f-2)=7(3f+22) equation: 



8(2f-2)=7(3f+22)

We move all terms to the left:

8(2f-2)-(7(3f+22))=0

We multiply parentheses

16f-(7(3f+22))-16=0



We calculate terms in parentheses: -(7(3f+22)), so:

7(3f+22)

We multiply parentheses

21f+154

Back to the equation:

-(21f+154)



We get rid of parentheses

16f-21f-154-16=0

We add all the numbers together, and all the variables

-5f-170=0

We move all terms containing f to the left, all other terms to the right

-5f=170

f=170/-5

f=-34

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