8(2l+4)=128

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Solution for 8(2l+4)=128 equation: 



8(2l+4)=128

We move all terms to the left:

8(2l+4)-(128)=0

We multiply parentheses

16l+32-128=0

We add all the numbers together, and all the variables

16l-96=0

We move all terms containing l to the left, all other terms to the right

16l=96

l=96/16

l=6

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