8(2n+3)-5(2n+8)=38-4(1-5n)

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Solution for 8(2n+3)-5(2n+8)=38-4(1-5n) equation: 



8(2n+3)-5(2n+8)=38-4(1-5n)

We move all terms to the left:

8(2n+3)-5(2n+8)-(38-4(1-5n))=0

We add all the numbers together, and all the variables

8(2n+3)-5(2n+8)-(38-4(-5n+1))=0

We multiply parentheses

16n-10n-(38-4(-5n+1))+24-40=0



We calculate terms in parentheses: -(38-4(-5n+1)), so:

38-4(-5n+1)

determiningTheFunctionDomain
-4(-5n+1)+38

We multiply parentheses

20n-4+38

We add all the numbers together, and all the variables

20n+34

Back to the equation:

-(20n+34)



We add all the numbers together, and all the variables

6n-(20n+34)-16=0

We get rid of parentheses

6n-20n-34-16=0

We add all the numbers together, and all the variables

-14n-50=0

We move all terms containing n to the left, all other terms to the right

-14n=50

n=50/-14

n=-3+4/7

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