8(2n-3)=(2n+2)+5

Solution for 8(2n-3)=(2n+2)+5 equation:

8(2n-3)=(2n+2)+5

We move all terms to the left:

8(2n-3)-((2n+2)+5)=0

We multiply parentheses

16n-((2n+2)+5)-24=0


We calculate terms in parentheses: -((2n+2)+5), so:

(2n+2)+5

We get rid of parentheses

2n+2+5

We add all the numbers together, and all the variables

2n+7

Back to the equation:

-(2n+7)


We get rid of parentheses

16n-2n-7-24=0

We add all the numbers together, and all the variables

14n-31=0

We move all terms containing n to the left, all other terms to the right

14n=31

n=31/14

n=2+3/14