8(2n-7)=2(n+1)

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Solution for 8(2n-7)=2(n+1) equation: 



8(2n-7)=2(n+1)

We move all terms to the left:

8(2n-7)-(2(n+1))=0

We multiply parentheses

16n-(2(n+1))-56=0



We calculate terms in parentheses: -(2(n+1)), so:

2(n+1)

We multiply parentheses

2n+2

Back to the equation:

-(2n+2)



We get rid of parentheses

16n-2n-2-56=0

We add all the numbers together, and all the variables

14n-58=0

We move all terms containing n to the left, all other terms to the right

14n=58

n=58/14

n=4+1/7

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