8(2n-8)=4(7+2n)-4

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Solution for 8(2n-8)=4(7+2n)-4 equation: 



8(2n-8)=4(7+2n)-4

We move all terms to the left:

8(2n-8)-(4(7+2n)-4)=0

We add all the numbers together, and all the variables

8(2n-8)-(4(2n+7)-4)=0

We multiply parentheses

16n-(4(2n+7)-4)-64=0



We calculate terms in parentheses: -(4(2n+7)-4), so:

4(2n+7)-4

We multiply parentheses

8n+28-4

We add all the numbers together, and all the variables

8n+24

Back to the equation:

-(8n+24)



We get rid of parentheses

16n-8n-24-64=0

We add all the numbers together, and all the variables

8n-88=0

We move all terms containing n to the left, all other terms to the right

8n=88

n=88/8

n=11

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