8(2r-1)=(1-r)+6

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Solution for 8(2r-1)=(1-r)+6 equation: 



8(2r-1)=(1-r)+6

We move all terms to the left:

8(2r-1)-((1-r)+6)=0

We add all the numbers together, and all the variables

8(2r-1)-((-1r+1)+6)=0

We multiply parentheses

16r-((-1r+1)+6)-8=0



We calculate terms in parentheses: -((-1r+1)+6), so:

(-1r+1)+6

We get rid of parentheses

-1r+1+6

We add all the numbers together, and all the variables

-1r+7

Back to the equation:

-(-1r+7)



We get rid of parentheses

16r+1r-7-8=0

We add all the numbers together, and all the variables

17r-15=0

We move all terms containing r to the left, all other terms to the right

17r=15

r=15/17

r=15/17

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