8(2r-4)-r=3(3r+2)

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Solution for 8(2r-4)-r=3(3r+2) equation:



8(2r-4)-r=3(3r+2)
We move all terms to the left:
8(2r-4)-r-(3(3r+2))=0
We add all the numbers together, and all the variables
-1r+8(2r-4)-(3(3r+2))=0
We multiply parentheses
-1r+16r-(3(3r+2))-32=0
We calculate terms in parentheses: -(3(3r+2)), so:
3(3r+2)
We multiply parentheses
9r+6
Back to the equation:
-(9r+6)
We add all the numbers together, and all the variables
15r-(9r+6)-32=0
We get rid of parentheses
15r-9r-6-32=0
We add all the numbers together, and all the variables
6r-38=0
We move all terms containing r to the left, all other terms to the right
6r=38
r=38/6
r=6+1/3

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