8(2t+1)-11=t-(t+2)

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Solution for 8(2t+1)-11=t-(t+2) equation: 



8(2t+1)-11=t-(t+2)

We move all terms to the left:

8(2t+1)-11-(t-(t+2))=0

We multiply parentheses

16t-(t-(t+2))+8-11=0



We calculate terms in parentheses: -(t-(t+2)), so:

t-(t+2)

We get rid of parentheses

t-t-2

We add all the numbers together, and all the variables

-2

Back to the equation:

-(-2)



We add all the numbers together, and all the variables

16t-1=0

We move all terms containing t to the left, all other terms to the right

16t=1

t=1/16

t=1/16

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