8(2t+1)12=4(7t+7)

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Solution for 8(2t+1)12=4(7t+7) equation: 



8(2t+1)12=4(7t+7)

We move all terms to the left:

8(2t+1)12-(4(7t+7))=0

We multiply parentheses

192t-(4(7t+7))+96=0



We calculate terms in parentheses: -(4(7t+7)), so:

4(7t+7)

We multiply parentheses

28t+28

Back to the equation:

-(28t+28)



We get rid of parentheses

192t-28t-28+96=0

We add all the numbers together, and all the variables

164t+68=0

We move all terms containing t to the left, all other terms to the right

164t=-68

t=-68/164

t=-17/41

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