8(2t+1)=7(d-2)

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Solution for 8(2t+1)=7(d-2) equation:


Simplifying
8(2t + 1) = 7(d + -2)

Reorder the terms:
8(1 + 2t) = 7(d + -2)
(1 * 8 + 2t * 8) = 7(d + -2)
(8 + 16t) = 7(d + -2)

Reorder the terms:
8 + 16t = 7(-2 + d)
8 + 16t = (-2 * 7 + d * 7)
8 + 16t = (-14 + 7d)

Solving
8 + 16t = -14 + 7d

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + -8 + 16t = -14 + -8 + 7d

Combine like terms: 8 + -8 = 0
0 + 16t = -14 + -8 + 7d
16t = -14 + -8 + 7d

Combine like terms: -14 + -8 = -22
16t = -22 + 7d

Divide each side by '16'.
t = -1.375 + 0.4375d

Simplifying
t = -1.375 + 0.4375d

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