8(2v+2)=4(4v+3)+4

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Solution for 8(2v+2)=4(4v+3)+4 equation: 



8(2v+2)=4(4v+3)+4

We move all terms to the left:

8(2v+2)-(4(4v+3)+4)=0

We multiply parentheses

16v-(4(4v+3)+4)+16=0



We calculate terms in parentheses: -(4(4v+3)+4), so:

4(4v+3)+4

We multiply parentheses

16v+12+4

We add all the numbers together, and all the variables

16v+16

Back to the equation:

-(16v+16)



We get rid of parentheses

16v-16v-16+16=0

We add all the numbers together, and all the variables

=0

v=0/1

v=0

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