8(2x)+32=4(4x+8)

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Solution for 8(2x)+32=4(4x+8) equation: 



8(2x)+32=4(4x+8)

We move all terms to the left:

8(2x)+32-(4(4x+8))=0



We calculate terms in parentheses: -(4(4x+8)), so:

4(4x+8)

We multiply parentheses

16x+32

Back to the equation:

-(16x+32)



We get rid of parentheses

82x-16x-32+32=0

We add all the numbers together, and all the variables

66x=0

x=0/66

x=0

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