8(2x+1)-3(3x+2)=2(x+5)

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Solution for 8(2x+1)-3(3x+2)=2(x+5) equation: 



8(2x+1)-3(3x+2)=2(x+5)

We move all terms to the left:

8(2x+1)-3(3x+2)-(2(x+5))=0

We multiply parentheses

16x-9x-(2(x+5))+8-6=0



We calculate terms in parentheses: -(2(x+5)), so:

2(x+5)

We multiply parentheses

2x+10

Back to the equation:

-(2x+10)



We add all the numbers together, and all the variables

7x-(2x+10)+2=0

We get rid of parentheses

7x-2x-10+2=0

We add all the numbers together, and all the variables

5x-8=0

We move all terms containing x to the left, all other terms to the right

5x=8

x=8/5

x=1+3/5

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