8(2x+1)=4(3x+4)

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Solution for 8(2x+1)=4(3x+4) equation: 



8(2x+1)=4(3x+4)

We move all terms to the left:

8(2x+1)-(4(3x+4))=0

We multiply parentheses

16x-(4(3x+4))+8=0



We calculate terms in parentheses: -(4(3x+4)), so:

4(3x+4)

We multiply parentheses

12x+16

Back to the equation:

-(12x+16)



We get rid of parentheses

16x-12x-16+8=0

We add all the numbers together, and all the variables

4x-8=0

We move all terms containing x to the left, all other terms to the right

4x=8

x=8/4

x=2

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