8(2x+1)=5(3x-2)+21

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Solution for 8(2x+1)=5(3x-2)+21 equation: 



8(2x+1)=5(3x-2)+21

We move all terms to the left:

8(2x+1)-(5(3x-2)+21)=0

We multiply parentheses

16x-(5(3x-2)+21)+8=0



We calculate terms in parentheses: -(5(3x-2)+21), so:

5(3x-2)+21

We multiply parentheses

15x-10+21

We add all the numbers together, and all the variables

15x+11

Back to the equation:

-(15x+11)



We get rid of parentheses

16x-15x-11+8=0

We add all the numbers together, and all the variables

x-3=0

We move all terms containing x to the left, all other terms to the right

x=3

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