8(2x+2)-5=6(x-1)+23

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Solution for 8(2x+2)-5=6(x-1)+23 equation: 



8(2x+2)-5=6(x-1)+23

We move all terms to the left:

8(2x+2)-5-(6(x-1)+23)=0

We multiply parentheses

16x-(6(x-1)+23)+16-5=0



We calculate terms in parentheses: -(6(x-1)+23), so:

6(x-1)+23

We multiply parentheses

6x-6+23

We add all the numbers together, and all the variables

6x+17

Back to the equation:

-(6x+17)



We add all the numbers together, and all the variables

16x-(6x+17)+11=0

We get rid of parentheses

16x-6x-17+11=0

We add all the numbers together, and all the variables

10x-6=0

We move all terms containing x to the left, all other terms to the right

10x=6

x=6/10

x=3/5

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