8(2x+3x+2)=-2(2x-74)

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Solution for 8(2x+3x+2)=-2(2x-74) equation:



8(2x+3x+2)=-2(2x-74)
We move all terms to the left:
8(2x+3x+2)-(-2(2x-74))=0
We add all the numbers together, and all the variables
8(5x+2)-(-2(2x-74))=0
We multiply parentheses
40x-(-2(2x-74))+16=0
We calculate terms in parentheses: -(-2(2x-74)), so:
-2(2x-74)
We multiply parentheses
-4x+148
Back to the equation:
-(-4x+148)
We get rid of parentheses
40x+4x-148+16=0
We add all the numbers together, and all the variables
44x-132=0
We move all terms containing x to the left, all other terms to the right
44x=132
x=132/44
x=3

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