If it's not what You are looking for type in the equation solver your own equation and let us solve it.
8(2x+3x^2)=-4x+148
We move all terms to the left:
8(2x+3x^2)-(-4x+148)=0
We multiply parentheses
24x^2+16x-(-4x+148)=0
We get rid of parentheses
24x^2+16x+4x-148=0
We add all the numbers together, and all the variables
24x^2+20x-148=0
a = 24; b = 20; c = -148;
Δ = b2-4ac
Δ = 202-4·24·(-148)
Δ = 14608
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{14608}=\sqrt{16*913}=\sqrt{16}*\sqrt{913}=4\sqrt{913}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-4\sqrt{913}}{2*24}=\frac{-20-4\sqrt{913}}{48} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+4\sqrt{913}}{2*24}=\frac{-20+4\sqrt{913}}{48} $
| A6x-4=3x+2 | | 65=x+5+-9x | | -2=-1+r/9 | | 18x-18=7x+13 | | 2(3t+5)=4(2t-1) | | 5=-16t^2+49 | | (8x+1)(x+3)=0 | | 5(x-2)=5(x+2) | | 30+15x=120+10x | | 1/5x(x-10)=4/5 | | 6y－8－6－8y=4 | | -9(t-2)=3(t-6) | | 8x+1=7x-2=3x | | 8x-26=6 | | 0=-5+v/2 | | -5+k/9=-4 | | -5y+2(y-2)=8 | | 2+-z=5 | | -26=n-11 | | 9x^2-7x+5=0 | | -20;n/4=-4 | | 12-3x=8.7 | | -16=-4+4n | | 24/x=8,x | | -6x-20=86 | | 102=-3(6p+2) | | 0;3x+17=16 | | 4n-(-8n-8)=104 | | 60-(3c+4)=4(c+6)=c | | -2+b/2=2 | | 4;a=4 | | 4x-3=3×-1 |