8(2x+4)-32=128

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Solution for 8(2x+4)-32=128 equation: 



8(2x+4)-32=128

We move all terms to the left:

8(2x+4)-32-(128)=0

We add all the numbers together, and all the variables

8(2x+4)-160=0

We multiply parentheses

16x+32-160=0

We add all the numbers together, and all the variables

16x-128=0

We move all terms containing x to the left, all other terms to the right

16x=128

x=128/16

x=8

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