8(2x+5)-2(x+3)=11-5(x+3)

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Solution for 8(2x+5)-2(x+3)=11-5(x+3) equation:



8(2x+5)-2(x+3)=11-5(x+3)
We move all terms to the left:
8(2x+5)-2(x+3)-(11-5(x+3))=0
We multiply parentheses
16x-2x-(11-5(x+3))+40-6=0
We calculate terms in parentheses: -(11-5(x+3)), so:
11-5(x+3)
determiningTheFunctionDomain -5(x+3)+11
We multiply parentheses
-5x-15+11
We add all the numbers together, and all the variables
-5x-4
Back to the equation:
-(-5x-4)
We add all the numbers together, and all the variables
14x-(-5x-4)+34=0
We get rid of parentheses
14x+5x+4+34=0
We add all the numbers together, and all the variables
19x+38=0
We move all terms containing x to the left, all other terms to the right
19x=-38
x=-38/19
x=-2

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