8(2x+5)-7=3(3x+11)+7x

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Solution for 8(2x+5)-7=3(3x+11)+7x equation: 


Simplifying
8(2x + 5) + -7 = 3(3x + 11) + 7x

Reorder the terms:
8(5 + 2x) + -7 = 3(3x + 11) + 7x
(5 * 8 + 2x * 8) + -7 = 3(3x + 11) + 7x
(40 + 16x) + -7 = 3(3x + 11) + 7x

Reorder the terms:
40 + -7 + 16x = 3(3x + 11) + 7x

Combine like terms: 40 + -7 = 33
33 + 16x = 3(3x + 11) + 7x

Reorder the terms:
33 + 16x = 3(11 + 3x) + 7x
33 + 16x = (11 * 3 + 3x * 3) + 7x
33 + 16x = (33 + 9x) + 7x

Combine like terms: 9x + 7x = 16x
33 + 16x = 33 + 16x

Add '-33' to each side of the equation.
33 + -33 + 16x = 33 + -33 + 16x

Combine like terms: 33 + -33 = 0
0 + 16x = 33 + -33 + 16x
16x = 33 + -33 + 16x

Combine like terms: 33 + -33 = 0
16x = 0 + 16x
16x = 16x

Add '-16x' to each side of the equation.
16x + -16x = 16x + -16x

Combine like terms: 16x + -16x = 0
0 = 16x + -16x

Combine like terms: 16x + -16x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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