8(2x+5)=7(x+3)+15

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Solution for 8(2x+5)=7(x+3)+15 equation: 



8(2x+5)=7(x+3)+15

We move all terms to the left:

8(2x+5)-(7(x+3)+15)=0

We multiply parentheses

16x-(7(x+3)+15)+40=0



We calculate terms in parentheses: -(7(x+3)+15), so:

7(x+3)+15

We multiply parentheses

7x+21+15

We add all the numbers together, and all the variables

7x+36

Back to the equation:

-(7x+36)



We get rid of parentheses

16x-7x-36+40=0

We add all the numbers together, and all the variables

9x+4=0

We move all terms containing x to the left, all other terms to the right

9x=-4

x=-4/9

x=-4/9

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