8(2x+8)+8=6(1-x)

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Solution for 8(2x+8)+8=6(1-x) equation: 



8(2x+8)+8=6(1-x)

We move all terms to the left:

8(2x+8)+8-(6(1-x))=0

We add all the numbers together, and all the variables

8(2x+8)-(6(-1x+1))+8=0

We multiply parentheses

16x-(6(-1x+1))+64+8=0



We calculate terms in parentheses: -(6(-1x+1)), so:

6(-1x+1)

We multiply parentheses

-6x+6

Back to the equation:

-(-6x+6)



We add all the numbers together, and all the variables

16x-(-6x+6)+72=0

We get rid of parentheses

16x+6x-6+72=0

We add all the numbers together, and all the variables

22x+66=0

We move all terms containing x to the left, all other terms to the right

22x=-66

x=-66/22

x=-3

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