8(2x-10)+4=32=68

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Solution for 8(2x-10)+4=32=68 equation: 



8(2x-10)+4=32=68

We move all terms to the left:

8(2x-10)+4-(32)=0

We add all the numbers together, and all the variables

8(2x-10)-28=0

We multiply parentheses

16x-80-28=0

We add all the numbers together, and all the variables

16x-108=0

We move all terms containing x to the left, all other terms to the right

16x=108

x=108/16

x=6+3/4

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