8(2x-10)+8=32

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Solution for 8(2x-10)+8=32 equation:



8(2x-10)+8=32
We move all terms to the left:
8(2x-10)+8-(32)=0
We add all the numbers together, and all the variables
8(2x-10)-24=0
We multiply parentheses
16x-80-24=0
We add all the numbers together, and all the variables
16x-104=0
We move all terms containing x to the left, all other terms to the right
16x=104
x=104/16
x=6+1/2

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