8(2x-10)-6=8(x-3)+2

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Solution for 8(2x-10)-6=8(x-3)+2 equation:



8(2x-10)-6=8(x-3)+2
We move all terms to the left:
8(2x-10)-6-(8(x-3)+2)=0
We multiply parentheses
16x-(8(x-3)+2)-80-6=0
We calculate terms in parentheses: -(8(x-3)+2), so:
8(x-3)+2
We multiply parentheses
8x-24+2
We add all the numbers together, and all the variables
8x-22
Back to the equation:
-(8x-22)
We add all the numbers together, and all the variables
16x-(8x-22)-86=0
We get rid of parentheses
16x-8x+22-86=0
We add all the numbers together, and all the variables
8x-64=0
We move all terms containing x to the left, all other terms to the right
8x=64
x=64/8
x=8

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