8(2x-3)-2=-8(3x-2)

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Solution for 8(2x-3)-2=-8(3x-2) equation: 



8(2x-3)-2=-8(3x-2)

We move all terms to the left:

8(2x-3)-2-(-8(3x-2))=0

We multiply parentheses

16x-(-8(3x-2))-24-2=0



We calculate terms in parentheses: -(-8(3x-2)), so:

-8(3x-2)

We multiply parentheses

-24x+16

Back to the equation:

-(-24x+16)



We add all the numbers together, and all the variables

16x-(-24x+16)-26=0

We get rid of parentheses

16x+24x-16-26=0

We add all the numbers together, and all the variables

40x-42=0

We move all terms containing x to the left, all other terms to the right

40x=42

x=42/40

x=1+1/20

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