8(2x-3)-5(2x+8)=38-(1-5x)*4

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Solution for 8(2x-3)-5(2x+8)=38-(1-5x)*4 equation: 



8(2x-3)-5(2x+8)=38-(1-5x)*4

We move all terms to the left:

8(2x-3)-5(2x+8)-(38-(1-5x)*4)=0

We add all the numbers together, and all the variables

8(2x-3)-5(2x+8)-(38-(-5x+1)*4)=0

We multiply parentheses

16x-10x-(38-(-5x+1)*4)-24-40=0



We calculate terms in parentheses: -(38-(-5x+1)*4), so:

38-(-5x+1)*4

determiningTheFunctionDomain
-(-5x+1)*4+38

We multiply parentheses

20x-4+38

We add all the numbers together, and all the variables

20x+34

Back to the equation:

-(20x+34)



We add all the numbers together, and all the variables

6x-(20x+34)-64=0

We get rid of parentheses

6x-20x-34-64=0

We add all the numbers together, and all the variables

-14x-98=0

We move all terms containing x to the left, all other terms to the right

-14x=98

x=98/-14

x=-7

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