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8(2x-3)-5(3x-1)=7(3x+4)
We move all terms to the left:
8(2x-3)-5(3x-1)-(7(3x+4))=0
We multiply parentheses
16x-15x-(7(3x+4))-24+5=0
We calculate terms in parentheses: -(7(3x+4)), so:We add all the numbers together, and all the variables
7(3x+4)
We multiply parentheses
21x+28
Back to the equation:
-(21x+28)
x-(21x+28)-19=0
We get rid of parentheses
x-21x-28-19=0
We add all the numbers together, and all the variables
-20x-47=0
We move all terms containing x to the left, all other terms to the right
-20x=47
x=47/-20
x=-2+7/20
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