8(2x-4)+4x=10x+8

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Solution for 8(2x-4)+4x=10x+8 equation: 



8(2x-4)+4x=10x+8

We move all terms to the left:

8(2x-4)+4x-(10x+8)=0

We add all the numbers together, and all the variables

4x+8(2x-4)-(10x+8)=0

We multiply parentheses

4x+16x-(10x+8)-32=0

We get rid of parentheses

4x+16x-10x-8-32=0

We add all the numbers together, and all the variables

10x-40=0

We move all terms containing x to the left, all other terms to the right

10x=40

x=40/10

x=4

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