8(2x-4)=-4+28,x

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Solution for 8(2x-4)=-4+28,x equation: 



8(2x-4)=-4+28.x

We move all terms to the left:

8(2x-4)-(-4+28.x)=0

We add all the numbers together, and all the variables

8(2x-4)-(28.x-4)=0

We multiply parentheses

16x-(28.x-4)-32=0

We get rid of parentheses

16x-28.x+4-32=0

We add all the numbers together, and all the variables

-12x-28=0

We move all terms containing x to the left, all other terms to the right

-12x=28

x=28/-12

x=-2+1/3

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