8(2x-4)=128

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Solution for 8(2x-4)=128 equation: 



8(2x-4)=128

We move all terms to the left:

8(2x-4)-(128)=0

We multiply parentheses

16x-32-128=0

We add all the numbers together, and all the variables

16x-160=0

We move all terms containing x to the left, all other terms to the right

16x=160

x=160/16

x=10

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