8(2x-4)=40x-48

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Solution for 8(2x-4)=40x-48 equation: 



8(2x-4)=40x-48

We move all terms to the left:

8(2x-4)-(40x-48)=0

We multiply parentheses

16x-(40x-48)-32=0

We get rid of parentheses

16x-40x+48-32=0

We add all the numbers together, and all the variables

-24x+16=0

We move all terms containing x to the left, all other terms to the right

-24x=-16

x=-16/-24

x=2/3

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