8(2x-4)=4x-40+8+12x.

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Solution for 8(2x-4)=4x-40+8+12x. equation: 



8(2x-4)=4x-40+8+12x.

We move all terms to the left:

8(2x-4)-(4x-40+8+12x.)=0

We add all the numbers together, and all the variables

8(2x-4)-(4x+12x.-32)=0

We multiply parentheses

16x-(4x+12x.-32)-32=0

We get rid of parentheses

16x-4x-12x.+32-32=0

We add all the numbers together, and all the variables

12x-12x.=0

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