8(2x-4x)+40=2x-16

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Solution for 8(2x-4x)+40=2x-16 equation:



8(2x-4x)+40=2x-16
We move all terms to the left:
8(2x-4x)+40-(2x-16)=0
We add all the numbers together, and all the variables
8(-2x)-(2x-16)+40=0
We multiply parentheses
-16x-(2x-16)+40=0
We get rid of parentheses
-16x-2x+16+40=0
We add all the numbers together, and all the variables
-18x+56=0
We move all terms containing x to the left, all other terms to the right
-18x=-56
x=-56/-18
x=3+1/9

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